Make the curve y=ax³+bx²+cx+d have a critical point at (0,-2) and also be a tangent to the line 3x+y+3=0 at (-1,0).
Make the curve y=ax³+bx²+cx+d have a critical point at (0,-2) and also be a tangent to the line 3x+y+3=0 at (-1,0).
Ans nya po is y=x³+3x²-2. Salamat po
- Log in to post comments
Substitute (0, -2) to the
Substitute (0, -2) to the given
Result: d = -2
Substitute (-1, 0) to the given
Result: -a + b - c = 1 ← Eq. (i)
Differentiate
Result: y' = 3ax2 + 2bx + c ← Eq. (ii)
Set y' = 0 at (0, -2)
Result: c = 0
Differentiate the line
Result: y' = -3
Set y' = -3 at (-1, 0) to Eq. (ii)
Result: 3a - 2b = -3 ← Eq. (iii)
Solve Eq. (i) and Eq. (iii) to find a and b.
-a+b-c=2 po sir sa Eqn 1. D=
In reply to Substitute (0, -2) to the by Jhun Vert
-a+b-c=2 po sir sa Eqn 1. D=-2 po.
Thanks sir
D ko po makuha values nila
In reply to -a+b-c=2 po sir sa Eqn 1. D= by Francis June E…
Nakuha ko na po sir. Salamat
Nakuha ko na po sir. Salamat po
Di na ako nag double check sa
In reply to Nakuha ko na po sir. Salamat by Francis June E…
Di na ako nag double check sa solution. I-comment mo lang sa post mo kung nakuha mo ang tamang equation.
Nakuha ko na po sir. Salamat
In reply to Di na ako nag double check sa by Jhun Vert
Nakuha ko na po sir. Salamat po
Paano niyo po nakuha ang
Paano niyo po nakuha ang sagot???