Make the curve y=ax³+bx²+cx+d have a critical point at (0,-2) and also be a tangent to the line 3x+y+3=0 at (-1,0).

Make the curve y=ax³+bx²+cx+d have a critical point at (0,-2) and also be a tangent to the line 3x+y+3=0 at (-1,0).
Ans nya po is y=x³+3x²-2. Salamat po

Substitute (0, -2) to the

Substitute (0, -2) to the given
Result: d = -2

Substitute (-1, 0) to the given
Result: -a + b - c = 1   ←   Eq. (i)

Differentiate
Result: y' = 3ax2 + 2bx + c   ←   Eq. (ii)

Set y' = 0 at (0, -2)
Result: c = 0

Differentiate the line
Result: y' = -3

Set y' = -3 at (-1, 0) to Eq. (ii)
Result: 3a - 2b = -3   ←   Eq. (iii)

Solve Eq. (i) and Eq. (iii) to find a and b.

-a+b-c=2 po sir sa Eqn 1. D=

-a+b-c=2 po sir sa Eqn 1. D=-2 po.

Thanks sir

D ko po makuha values nila

D ko po makuha values nila sir.

Nakuha ko na po sir. Salamat

Nakuha ko na po sir. Salamat po

Di na ako nag double check sa

Di na ako nag double check sa solution. I-comment mo lang sa post mo kung nakuha mo ang tamang equation.

Nakuha ko na po sir. Salamat

Nakuha ko na po sir. Salamat po

Paano niyo po nakuha ang

Paano niyo po nakuha ang sagot???