# Differential Equations: (3y - 2yx^2)[ 1 + ln^2 (2x^3 / 3y^2) ] dx - 2x dy = 0

Submitted by agentcollins on July 17, 2016 - 10:22am

The topic is Additional Topics in Ordinary DE of the first order. Thank you so much.

3y-2yx^2 [ 1 + (ln (2x^3 / 3y^2))^2 ]dx - 2xdy =0

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## do you mean this?

do you mean this?

(3y-2yx^2)[ 1 + (ln (2x^3 / 3y^2))^2 ]dx - 2xdy =0

## Yes sir.

[(3y-2yx^2) [ 1 + (ln (2x^3 / 3y^2))^2 ]]dx - 2xdy =0

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