Differential Equations: (3y - 2yx^2)[ 1 + ln^2 (2x^3 / 3y^2) ] dx - 2x dy = 0

The topic is Additional Topics in Ordinary DE of the first order. Thank you so much.

3y-2yx^2 [ 1 + (ln (2x^3 / 3y^2))^2 ]dx - 2xdy =0

Jhun Vert's picture

do you mean this?

(3y-2yx^2)[ 1 + (ln (2x^3 / 3y^2))^2 ]dx - 2xdy =0

[(3y-2yx^2) [ 1 + (ln (2x^3 / 3y^2))^2 ]]dx - 2xdy =0

Add new comment

Deafult Input

  • Allowed HTML tags: <img> <em> <strong> <cite> <code> <ul> <ol> <li> <dl> <dt> <dd> <sub> <sup> <blockquote> <ins> <del> <div>
  • Web page addresses and e-mail addresses turn into links automatically.
  • Lines and paragraphs break automatically.
  • Mathematics inside the configured delimiters is rendered by MathJax. The default math delimiters are $$...$$ and \[...\] for displayed mathematics, and $...$ and \(...\) for in-line mathematics.

Plain text

  • No HTML tags allowed.
  • Lines and paragraphs break automatically.