Differential Equations: (3y - 2yx^2)[ 1 + ln^2 (2x^3 / 3y^2) ] dx - 2x dy = 0
The topic is Additional Topics in Ordinary DE of the first order. Thank you so much.
3y-2yx^2 [ 1 + (ln (2x^3 / 3y^2))^2 ]dx - 2xdy =0
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do you mean this?
do you mean this?
(3y-2yx^2)[ 1 + (ln (2x^3 / 3y^2))^2 ]dx - 2xdy =0
Yes sir.
In reply to do you mean this? by Jhun Vert
[(3y-2yx^2) [ 1 + (ln (2x^3 / 3y^2))^2 ]]dx - 2xdy =0