# Differential Equations: Bernoulli's Equation $1 - 3rss' + r^2 s^2 s' = 0$

Bernoulli?

1- 3rss' + r^2 s^2 s' =0

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Bernoulli?

1- 3rss' + r^2 s^2 s' =0

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## Yes, the given is a Bernoulli

Yes, the given is a Bernoulli's equation

$1 - 3rs\,s' + r^2 s^2\,s' =0$

$1 - 3rs \, \dfrac{ds}{dr} + r^2 s^2 \, \dfrac{ds}{dr} = 0$

$dr - 3rs \, ds + r^2 s^2 \, ds = 0$

$dr - 3sr \, ds = -s^2 r^2 \, ds$

The equation is in the form

$dr + P(s) \, r \, ds = Q(s) \, r^n \, ds$