detailed solution please? total energy of rotating rod
the rod is 10ft long weighing 20lbs. if it revolves through one end at 2rps, find the total energy.
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Use the formula for kinetic
Use the formula for kinetic energy of rotating rod:
KE = energy due to rotation + energy due to translation of center of mass
$KE = \frac{1}{2}I\omega^2 + \frac{1}{2}mv^2$