Arbitrary constant Submitted by danedison on Thu, 09/14/2017 - 19:26 y=x^2+C1e^2x+C2e^3x Thank you again Tags Differential Equation, DE Log in to post comments $y = x^2 + c_1 e^{2x} + c_2 e Jhun Vert Sat, 10/28/2017 - 14:45 $y = x^2 + c_1 e^{2x} + c_2 e^{3x}$ ← Equation (1) $y' = 2x + 2c_1 e^{2x} + 3c_2 e^{3x}$ ← Equation (2) $y'' = 2 + 4c_1 e^{2x} + 9c_2 e^{3x}$ ← Equation (3) Equation (2) - 3 × Equation (1) $y' - y = (2x - 3x^2) - c_1 e^{2x}$ ← Equation (4) Equation (3) - 3 × Equation (2) $y'' - y' = (2 - 6x) - 2c_1 e^{2x}$ ← Equation (5) Equation (5) - 2 × Equation (4) $(y'' - y') - 2(y' - y) = (2 - 6x) - 2(2x - 3x^2)$ $y'' - 3y' + 2y = 2 - 10x + 6x^2$ ← (answer) Log in to post comments
$y = x^2 + c_1 e^{2x} + c_2 e Jhun Vert Sat, 10/28/2017 - 14:45 $y = x^2 + c_1 e^{2x} + c_2 e^{3x}$ ← Equation (1) $y' = 2x + 2c_1 e^{2x} + 3c_2 e^{3x}$ ← Equation (2) $y'' = 2 + 4c_1 e^{2x} + 9c_2 e^{3x}$ ← Equation (3) Equation (2) - 3 × Equation (1) $y' - y = (2x - 3x^2) - c_1 e^{2x}$ ← Equation (4) Equation (3) - 3 × Equation (2) $y'' - y' = (2 - 6x) - 2c_1 e^{2x}$ ← Equation (5) Equation (5) - 2 × Equation (4) $(y'' - y') - 2(y' - y) = (2 - 6x) - 2(2x - 3x^2)$ $y'' - 3y' + 2y = 2 - 10x + 6x^2$ ← (answer) Log in to post comments
$y = x^2 + c_1 e^{2x} + c_2 e
$y = x^2 + c_1 e^{2x} + c_2 e^{3x}$ ← Equation (1)
$y' = 2x + 2c_1 e^{2x} + 3c_2 e^{3x}$ ← Equation (2)
$y'' = 2 + 4c_1 e^{2x} + 9c_2 e^{3x}$ ← Equation (3)
Equation (2) - 3 × Equation (1)
$y' - y = (2x - 3x^2) - c_1 e^{2x}$ ← Equation (4)
Equation (3) - 3 × Equation (2)
$y'' - y' = (2 - 6x) - 2c_1 e^{2x}$ ← Equation (5)
Equation (5) - 2 × Equation (4)
$(y'' - y') - 2(y' - y) = (2 - 6x) - 2(2x - 3x^2)$
$y'' - 3y' + 2y = 2 - 10x + 6x^2$ ← (answer)