Active forum topics
- Hydraulics: Rotating Vessel
- Inverse Trigo
- General Solution of $y' = x \, \ln x$
- engineering economics: construct the cash flow diagram
- Eliminate the Arbitrary Constants
- Law of cosines
- Maxima and minima (trapezoidal gutter)
- Special products and factoring
- Integration of 4x^2/csc^3x√sinxcosx dx
- application of minima and maxima
New forum topics
- Hydraulics: Rotating Vessel
- Inverse Trigo
- General Solution of $y' = x \, \ln x$
- engineering economics: construct the cash flow diagram
- Integration of 4x^2/csc^3x√sinxcosx dx
- Maxima and minima (trapezoidal gutter)
- Special products and factoring
- Newton's Law of Cooling
- Law of cosines
- Can you help me po to solve this?
Recent comments
- Determine the least depth…2 weeks ago
- Solve mo ang h manually…3 weeks 5 days ago
- Paano kinuha yung height na…3 weeks 5 days ago
- It's the unit conversion…1 month ago
- Refer to the figure below…1 month ago
- Yes.4 months 3 weeks ago
- Sir what if we want to find…4 months 3 weeks ago
- Hello po! Question lang po…5 months 1 week ago
- 400000=120[14π(D2−10000)]
(…6 months 2 weeks ago - Use integration by parts for…7 months 2 weeks ago
To get the average speed for
To get the average speed for the round trip, recall that...
$$distance = (speed)(time)$$ $$d = vt$$
We also know that $$average \space speed = \frac{total \space distance}{total \space time}$$
With that in mind...
The time required by train (a flying train, I suppose, hehe) to reach its destination is $\frac{X}{160}$ hours. The time required by train to return from its destination is $\frac{X}{240}$ hours.
So...
The total distance for the round trip would be $X+X = 2X$ miles.
The total time spent flying would be $\frac{X}{160}+\frac{X}{240} = \frac{X}{96}$ hours.
Therefore, the average speed for the entire round trip would be $\frac{2X \space miles}{\frac{X}{96} \space hours}$ = $\color{green}{192 \space miles \space per \space hour}$
Alternate solutions are encouraged...