# Differential Equation

## Differential Equation: $(1-xy)^{-2} dx + \left[ y^2 + x^2 (1-xy)^{-2} \right] dy = 0$

Submitted by The Organist on December 11, 2020 - 1:12am

Hello, can anyone solve this equation?

I can't figure it out,

$(1-xy)^{-2} dx + \left[ y^2 + x^2 (1-xy)^{-2} \right] dy = 0$

Thanks.

## DE: $(x²+4) y' + 3 xy = x$

Submitted by Sydney Sales on September 19, 2016 - 2:55pm

(x²+4) y' + 3 xy = x

## bernoulli: $(y^4 - 2xy) dx + 3 x^2 dy= 0$

Submitted by Sydney Sales on September 5, 2016 - 12:19pm

(y^4 - 2xy) dx + 3 x^2 dy= 0

## Differential Equation $2y \, dx+x(x^2 \ln y -1) \, dy = 0$

Submitted by qwerty on August 6, 2016 - 9:58pm

Please help me solve this Differential Equation

2ydx+x(x^{2}lny -1)dy=0

## Differential Equation: $ye^{xy} dx + xe^{xy} dy = 0$

Submitted by qwerty on July 17, 2016 - 8:28am

Please help me to solve this differential equation

ye^{xy}dx+xe^{xy}dy=0

## DE: $x \, dx + [ sin^2 (y/x) ](y \, dx - x \, dy) = 0$

Submitted by Sydney Sales on July 16, 2016 - 3:08pm

xdx + sin^2 ( y/x ) [ ydx - xdy ] = 0

## differential equation: Determine whether a member of the family can be found that satisfies the initial conditions

Submitted by Dutsky Kamdon on February 1, 2016 - 10:27pm

The given two-parameter family is a solution of the indicated differential equation on the

interval (−∞,∞). Determine whether a member of the family can be found that satisfies the

initial conditions.

y = c1e^x cos x + c2e^x sin x; y" − 2y' + 2y = 0,

i. y(0) = 1, y'(π) = 0

ii. y(0) = 1, y(π) = −1