# Differential Equation

## Differential Equation: (1-xy)^-2 dx + [y^2 + x^2 (1-xy)^-2] dy = 0

Hello, can anyone solve this equation?

I can't figure it out,

(1-xy)^-2 dx + [y^2 + x^2 (1-xy)^-2] dy = 0

Thanks.

## DE: (x²+4) y' + 3 xy = x

(x²+4) y' + 3 xy = x

## bernoulli: (y^4 - 2xy) dx + 3 x^2 dy= 0

(y^4 - 2xy) dx + 3 x^2 dy= 0