Differential Equation

Differential Equation: (1-xy)^-2 dx + [y^2 + x^2 (1-xy)^-2] dy = 0

Hello, can anyone solve this equation?

I can't figure it out,

(1-xy)^-2 dx + [y^2 + x^2 (1-xy)^-2] dy = 0

Thanks.

Sydney Sales's picture

DE: (x²+4) y' + 3 xy = x

(x²+4) y' + 3 xy = x

Sydney Sales's picture

bernoulli: (y^4 - 2xy) dx + 3 x^2 dy= 0

(y^4 - 2xy) dx + 3 x^2 dy= 0

Dutsky Kamdon's picture

differential equation: Determine whether a member of the family can be found that satisfies the initial conditions

The given two-parameter family is a solution of the indicated differential equation on the
interval (−∞,∞). Determine whether a member of the family can be found that satisfies the
initial conditions.
y = c1e^x cos x + c2e^x sin x; y" − 2y' + 2y = 0,
i. y(0) = 1, y'(π) = 0
ii. y(0) = 1, y(π) = −1

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