Bernoulli's differential equation

Part (a) xdy + ydx = x^3 y^6 dx
$x \, dy + y \, dx = x^3 y^6 \, dx$

$dy + \dfrac{1}{x}y \, dx = x^2 y^6 \, dx$

Integrating Factor
$\begin{align}
\displaystyle u & = e^{(1 - n)\int P\,dx} \\
& = e^{-5\int \frac{1}{x}\,dx} \\
& = e^{-5 \ln x} \\
& = e^{\ln x^{-5}} \\
& = x^{-5}
\end{align}$
 

Thus,
$\displaystyle zu = (1 - n) \int Qu \, dx + C$

$\displaystyle y^{-5}x^{-5} = -5 \int x^2 (x^{-5}) \, dx + C$

$\displaystyle x^{-5}y^{-5} = -5 \int x^{-3} \, dx + C$

$x^{-5}y^{-5} = -5 \left( \dfrac{x^{-2}}{-2} \right) + C$

$x^{-5}y^{-5} = \frac{5}{2} x^{-2} + C$