Active forum topics
- Inverse Trigo
- General Solution of $y' = x \, \ln x$
- engineering economics: construct the cash flow diagram
- Eliminate the Arbitrary Constants
- Law of cosines
- Maxima and minima (trapezoidal gutter)
- Special products and factoring
- Integration of 4x^2/csc^3x√sinxcosx dx
- application of minima and maxima
- Sight Distance of Vertical Parabolic Curve
New forum topics
- Inverse Trigo
- General Solution of $y' = x \, \ln x$
- engineering economics: construct the cash flow diagram
- Integration of 4x^2/csc^3x√sinxcosx dx
- Maxima and minima (trapezoidal gutter)
- Special products and factoring
- Newton's Law of Cooling
- Law of cosines
- Can you help me po to solve this?
- Eliminate the Arbitrary Constants
Recent comments
- Yes.4 days 8 hours ago
- Sir what if we want to find…4 days 8 hours ago
- Hello po! Question lang po…3 weeks 1 day ago
- 400000=120[14π(D2−10000)]
(…1 month 3 weeks ago - Use integration by parts for…2 months 3 weeks ago
- need answer2 months 3 weeks ago
- Yes you are absolutely right…2 months 3 weeks ago
- I think what is ask is the…2 months 3 weeks ago
- $\cos \theta = \dfrac{2}{…2 months 3 weeks ago
- Why did you use (1/SQ root 5…2 months 3 weeks ago
$\mathbf{For \space the
$\mathbf{For \space the \space first \space question:}$
We need a picture to visualize the problem.
Looking deeper at the picture, we found out that the section made by a plane running parallel through the cylinder axis and wetted diameter is a:
$$\color{blue}{\mathbf{Parabolic \space Segment}}$$
Well...it does look like an ellipse broke into two equal parts though...
$\mathbf{For \space the \space second \space question:}$
We need a picture to visualize the problem.
Looking deeper at the picture, we found out that the section made by a plane running perpendicular through the wetted diameter is a:
$$\color{blue}{\mathbf{Right \space Triangle}}$$
Alternate solutions are encouraged....