elastic curve

Problem 632
For the beam loaded as shown in Fig. P-632, compute the value of (Area_AB) barred(X)_A. From this result, is the tangent drawn to the elastic curve at B directed up or down to the right? (Hint: Refer to the deviation equations and rules of sign.)
 

Problem 630
For the beam loaded as shown in Fig. P-630, compute the value of (Area_AB)barred(X)_A . From the result determine whether the tangent drawn to the elastic curve at B slopes up or down to the right. (Hint: Refer to the deviation equations and rules of sign.)
 

Problem 621
Determine the value of EIδ midway between the supports for the beam shown in Fig. P-621. Check your result by letting a = 0 and comparing with Prob. 606. (Apply the hint given in Prob. 620.)
 

Problem 620
Find the midspan deflection δ for the beam shown in Fig. P-620, carrying two triangularly distributed loads. (Hint: For convenience, select the origin of the axes at the midspan position of the elastic curve.)
 

Problem 619
Determine the value of EIy midway between the supports for the beam loaded as shown in Fig. P-619.
 

Problem 618
A simply supported beam carries a couple M applied as shown in Fig. P-618. Determine the equation of the elastic curve and the deflection at the point of application of the couple. Then letting a = L and a = 0, compare your solution of the elastic curve with cases 11 and 12 in the Summary of Beam Loadings.
 

Problem 614
For the beam loaded as shown in Fig. P-614, calculate the slope of the elastic curve over the right support.
 

Problem 608
Find the equation of the elastic curve for the cantilever beam shown in Fig. P-608; it carries a load that varies from zero at the wall to w_o at the free end. Take the origin at the wall.
 

Problem 607
Determine the maximum value of EIy for the cantilever beam loaded as shown in Fig. P-607. Take the origin at the wall.
 

Problem 606
Determine the maximum deflection δ in a simply supported beam of length L carrying a uniformly distributed load of intensity w_o applied over its entire length.