Solution to Problem 447 | Relationship Between Load, Shear, and Moment

1. A 2400 lb upward force is acting at point A. No load in segment AB.
2. A point force of 2400 - 400 = 2000 lb is acting downward at point B. No load in segment BC.
3. Another downward force of magnitude 400 + 4000 = 4400 lb at point C. No load in segment CD.
4. Upward point force of 4000 + 1000 = 5000 lb is acting at D. No load in segment DE.
5. A downward force of 1000 lb is concentrated at point E.

To draw the Moment Diagram

1. M_A = 0
2. M_B = M_A + Area in shear diagram
   M_B = 0 + 2400(2) = 4800 lb·ft
   M_AB is linear and upward
3. M_C = M_B + Area in shear diagram
   M_C = 4800 + 400(3) = 6000 lb·ft
   M_BC is linear and upward
4. M_D = M_C + Area in shear diagram
   M_D = 6000 - 4000(2) = -2000 lb·ft
   M_CD is linear and downward
5. M_E = M_D + Area in shear diagram
   M_E = -2000 + 1000(2) = 0
   M_DE is linear and upward