$\displaystyle \int \dfrac{2x^3+5x^2-4}{x^2}dx$
$\,\,\,\,\,\,\,\,\,\, = \displaystyle \int \left( \dfrac{2x^3}{x^2} + \dfrac{5x^2}{x^2} - \dfrac{4}{x^2} \right) dx$
$\,\,\,\,\,\,\,\,\,\, = \displaystyle \int ( 2x + 5 - 4x^{-2} ) \, dx$
$\,\,\,\,\,\,\,\,\,\, = \displaystyle \int ( 2x + 5 - 4x^{-2} ) \, dx$
$\,\,\,\,\,\,\,\,\,\, = \displaystyle 2\int x\,dx + 5\int dx - 4\int x^{-2} \, dx$
$\,\,\,\,\,\,\,\,\,\, = \dfrac{2x^2}{2} + 5x - \dfrac{4x^{-1}}{-1} + C$
$\,\,\,\,\,\,\,\,\,\, = x^2 + 5x + \dfrac{4}{x} + C$ answer