Problem 03 - Variation of Pressure

Mass density of sea water
$\gamma_{sea \,\, water} = 1.03(9.79)$
$\gamma_{sea \,\, water} = 10.0837 \, \text{kN/m}^3$
$\rho_{sea \,\, water} = 10.0837 \, \dfrac{\text{kN}}{\text{m}^3} \left( 1\,000 \, \dfrac{\text{N}}{\text{kN}} \right) \left( \dfrac{1}{9.81 \, \text{m/s}^2} \right)$
$\rho_{sea \,\, water} = 1027.90 \, \text{kg/m}^3$

Thus,
$p = 1027.90(3.22 \times 1000)$
$p = 3\,309\,838 ~ \text{kg/m}^2$
$p = 3\,309.84 \, \text{tonne/m}^2$           answer