$p = \rho h$

- Mass density of sea water

$\gamma_{sea \,\, water} = 1.03(9.79)$

$\gamma_{sea \,\, water} = 10.0837 \, \text{kN/m}^3$

$\rho_{sea \,\, water} = 10.0837 \, \dfrac{\text{kN}}{\text{m}^3} \left( 1\,000 \, \dfrac{\text{N}}{\text{kN}} \right) \left( \dfrac{1}{9.81 \, \text{m/s}^2} \right)$

$\rho_{sea \,\, water} = 1027.90 \, \text{kg/m}^3$

Thus,

$p = 1027.90(3.22 \times 1000)$

$p = 3\,309\,838 ~ \text{kg/m}^2$

$p = 3\,309.84 \, \text{tonne/m}^2$ *answer*