Multiply Equation (1) by 3
$\dfrac{9}{x^2} - \dfrac{12}{y^2} = 6$ ← Equation (3)
Multiply Equation (2) by 4
$\dfrac{20}{x^2} - \dfrac{12}{y^2} = 17$ ← Equation (2)
Subtract Equation (3) from Equation (4)
$\dfrac{11}{x^2} = 11$
$x^2 = 1$
$x = \pm 1$
Substitute x = ±1 to Equation (1)
$3 - \dfrac{4}{y^2} = 2$
$1 = \dfrac{4}{y^2}$
$y^2 = 4$
$y = \pm 2$
The solutions are
(1, 2), (1, -2), (-1, 2), and (-1, -2) answer