from a point A 10 cm from a plane P, a perpendicular line AC is drawn passing through a circle with center C and radius of 8 cm in the plane. At any point B on this circle, a tangent BD is drawn 18 cm in length. FInd the distance from A to D.

March 22, 2016 - 9:59am

#1
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from a point A 10 cm from a plane P, a perpendicular line AC is drawn passing through a circle with center C and radius of 8 cm in the plane. At any point B on this circle, a tangent BD is drawn 18 cm in length. FInd the distance from A to D.

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To answer the problem above, kailangan natin ng drowing....hehehe

The figure that describes the problem looks like this:

To get the distance between points $A$ and $D$, we need to get the $s$ first. Using the Pythagorean theorem:

$$s^2 = (10 \space cm)^2 + (8 \space cm)^2$$ $$s = 12.8 \space cm$$

Now getting the distance between points $A$ and $D$ (denoted as $h$) using the Pythagorean theorem:

$$h^2 = (12.8 \space cm)^2 + (18 \space cm)^2$$ $$h = 22.1 \space cm$$

Therefore, the distance between the points $A$ and $D$ is $\color{green}{22.1 \space cm}$

Alternate solutions are encouraged....heheheh