Active forum topics
- Hydraulics: Rotating Vessel
- Inverse Trigo
- Application of Differential Equation: Newton's Law of Cooling
- Problems in progression
- General Solution of $y' = x \, \ln x$
- engineering economics: construct the cash flow diagram
- Eliminate the Arbitrary Constants
- Law of cosines
- Maxima and minima (trapezoidal gutter)
- Special products and factoring
New forum topics
- Hydraulics: Rotating Vessel
- Inverse Trigo
- Problems in progression
- General Solution of $y' = x \, \ln x$
- engineering economics: construct the cash flow diagram
- Integration of 4x^2/csc^3x√sinxcosx dx
- Maxima and minima (trapezoidal gutter)
- Special products and factoring
- Newton's Law of Cooling
- Find the roots of the quadratic equation by differentiation method
Recent comments
- Bakit po nagmultiply ng 3/4…5 days 10 hours ago
- Determine the least depth…10 months ago
- Solve mo ang h manually…5 days 10 hours ago
- Paano kinuha yung height na…10 months 2 weeks ago
- It's the unit conversion…10 months 3 weeks ago
- Refer to the figure below…10 months 2 weeks ago
- where do you get the sqrt415 days 10 hours ago
- Thank you so much4 days 20 hours ago
- How did you get the 2.8 mins…4 days 19 hours ago
- How did you get the distance…4 days 19 hours ago


The present value can be
The present value can be thought of as the equivalent amount of money that would be paid up front as a lump sum, which has the same time value of money as the cash flow in question.
For example, if I say that $2000$ will be paid to you one year from now, and the effective annual rate of interest is $i=0.1$, the present value of this payment is the amount which, if held by you over the same amount of time, would equal $2000$ at the end of one year. That is to say....
$$Present \space value (1+i)= 2000$$
or
$$Present \space value = \frac{2000}{1+0.1} = 1818.18$$
So...it means that receiving $1818.18$ now and receiving $2000$ after a year, assuming its annual interest rate is $0.1$, means the same thing.
With that in mind, the present value of cash-flow would be:
I was paid $1000$, $2000$, $3000$, $4000$ and $5000$ after now, $1$, $2$, $3$, and $4$ years, respectively. Translating into an equation, it becomes...
$$1000 + \frac{2000}{(1+0.1)^1} + \frac{3000}{(1+0.1)^2} + \frac{4000}{(1+0.1)^3} + \frac{5000}{(1+0.1)^4}$$
which equals $11717.85$
Therefore, the present value of the cash flow would be $\color{green}{11717.85}$ pesos.
Alternate solutions are highly encouraged....