Discussion on: Solution to Problem 115 Shear Stress
Following is a discussion on the Reviewer item titled: Solution to Problem 115 Shear Stress. Feel free to add your own comments!
- Log in to post comments
Active forum topics
- Deriving trigonometric function
- Eliminate the Arbitrary Constants
- Law of cosines
- Maxima and minima (trapezoidal gutter)
- Special products and factoring
- Integration of 4x^2/csc^3x√sinxcosx dx
- application of minima and maxima
- Sight Distance of Vertical Parabolic Curve
- Application of Differential Equation: Newton's Law of Cooling
- Minima maxima: a²y = x⁴
New forum topics
- Integration of 4x^2/csc^3x√sinxcosx dx
- Maxima and minima (trapezoidal gutter)
- Special products and factoring
- Newton's Law of Cooling
- Law of cosines
- Can you help me po to solve this?
- Eliminate the Arbitrary Constants
- Required diameter of solid shaft
- Deriving trigonometric function
- Integration $\displaystyle \int \sec 2x ~ dx$
the area?
why is that the area of pi(r)squared all over 4 are not use in this problem?thanks
Re: the area?
In reply to the area? by VG Icalina
cause, only the out surface of the punch have shear stress. I think so LOL
Re: the area?
In reply to Re: the area? by Rod Tuardon Brizuela
thanks. it make sense..:-)
How did thry use thr height ,
How did thry use thr height , I mean why pie inti 20 into 25, is it r e rectangle formula