# Differential equation. how to solve?

1. (x^2 + 2xy - 4y^2) dx - ( x^2 - 8xy - 4 y^2)dy=0
2. y(9x-2y)dx-x(6x-y)dy=0; when: x=1; y=1/2

### both equation are homogeneous

both equation are homogeneous. You can use either of the following substitution:

1. y = vx
dy = v dx + x dv
2. x = vy
dx = v dy + y dv

The result would be separable equation which you can easily solve. And don't forget to revert back to original variables of x and y then apply boundary conditions as necessary.

### thank you po. ☺

thank you po. ☺

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