1. (x^2 + 2xy - 4y^2) dx - ( x^2 - 8xy - 4 y^2)dy=0
2. y(9x-2y)dx-x(6x-y)dy=0; when: x=1; y=1/2
Differential equation. how to solve?
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both equation are homogeneous. You can use either of the following substitution:
dy = v dx + x dv
dx = v dy + y dv
The result would be separable equation which you can easily solve. And don't forget to revert back to original variables of x and y then apply boundary conditions as necessary.
thank you po. ☺