Integration issue

$\begin{align}
\dfrac{p}{\dfrac{Ao\left( \dfrac{1 - x}{2L} \right)}{E}} & = \dfrac{2pEL}{Ao(1 - x)} \\
& = \dfrac{2pEL}{Ao} \cdot \dfrac{1}{1 - x}
\end{align}$
 

You posted this with a title "integration issue" under calculus, which I presume you wanted to do this:
$\displaystyle \dfrac{2pEL}{Ao} \int \dfrac{dx}{1 - x} = -\dfrac{2pEL}{Ao}\ln (1 - x) + C$
 

Side Note:

Allow me to bring up your previous post which is a little similar to the equation in this post.
 

 

The only difference is E.
 

Note that
$\dfrac{p}{\dfrac{Ao\left( \dfrac{1 - x}{2L} \right)}{E}} = \dfrac{p}{Ao\left( \dfrac{1 - x}{2L} \right)} * E$

while
$\dfrac{p}{Ao\left( \dfrac{1 - x}{2L} \right)} * E^{-1} = \dfrac{p}{AoE\left( \dfrac{1 - x}{2L} \right)}$
 

I am not sure though if this side note is still relevant to you.