Pedro can paint a fence 50% faster than Juan and 20% faster than Pilar and together they can paint a given fence in 4 hours. How long will it take Pedro to paint the same fence if he had to work alone?

Solution:

Let Rate of pedro = 1/t_{pedro} = x

Rate of juan = .50x

Rate of pilar = .80x

(x+.50x+.80x)4=1

2.3x=1/4

x=5/46

5/46 = 1/t_{pedro}

t_{pedro}=46/5 =9.2hours

Is this solution correct because the book says the answer is 10hours.

Consider these:

Rate of Juan = (2/3)*Rate of Pedro

Rate of Pilar = (5/6)*Rate of Pedro

Thank you sir. Just now i can see my analyzation is very wrong.

how it became 1.50 and 1.20?

50% faster is 100% + 50% or 1.5.

where did the 2/3 and 5/6 came from

calculator... 1 ÷ 1.5 = 2/3

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