Suppose 3 items are inspected and if at least one defective is found, the lot will be 100% inspected. Otherwise, the lot will be passed on. How likely it is that a lot containing 5 defectives will be passed on?

Jhun Vert's picture

Suppose the lot size is $N$. The sample size $n = 3$. The lot will be passed on if none of the 5 defectives got selected to $n$. Hence,

$P = \dfrac{\displaystyle{\binom{5}{0}} \cdot \displaystyle{\binom{N - 5}{3}}}{\displaystyle{\binom{N}{3}}}$

Add new comment

Deafult Input

  • Allowed HTML tags: <img> <em> <strong> <cite> <code> <ul> <ol> <li> <dl> <dt> <dd> <sub> <sup> <blockquote> <ins> <del> <div>
  • Web page addresses and e-mail addresses turn into links automatically.
  • Lines and paragraphs break automatically.
  • Mathematics inside the configured delimiters is rendered by MathJax. The default math delimiters are $$...$$ and \[...\] for displayed mathematics, and $...$ and \(...\) for in-line mathematics.

Plain text

  • No HTML tags allowed.
  • Lines and paragraphs break automatically.
This question is for testing whether or not you are a human visitor and to prevent automated spam submissions.