Liquid Level of Horizontal Tank at Algebra Forum

Hello,
I want to calculate the liquid level of a horizontal cylindrical tank. Consider the equation :

V=L{(Pi)R^2-R^2ArcCos[(R-h)/R]+(R-h)Sqrt(2Rh-h^2)}

V=Tank volume
L= Tank length
R= Tank radius
h= Distance from top of tank to surface of liquid

What I want to do is to rearrange the above equation so that h is the subject. can this be done?

fitzmerl duron Tue, 02/20/2018 - 11:27

Impossibleng makuha ang $h$. Nabuhol kasi sa $\arccos\left( \frac{R-h}{R} \right)$ at sa $\sqrt{2Rh-h^2}$.....hehehehehhe

Liquid Level of Horizontal Tank