Active forum topics
- Inverse Trigo
- General Solution of $y' = x \, \ln x$
- engineering economics: construct the cash flow diagram
- Eliminate the Arbitrary Constants
- Law of cosines
- Maxima and minima (trapezoidal gutter)
- Special products and factoring
- Integration of 4x^2/csc^3x√sinxcosx dx
- application of minima and maxima
- Sight Distance of Vertical Parabolic Curve
New forum topics
- Inverse Trigo
- General Solution of $y' = x \, \ln x$
- engineering economics: construct the cash flow diagram
- Integration of 4x^2/csc^3x√sinxcosx dx
- Maxima and minima (trapezoidal gutter)
- Special products and factoring
- Newton's Law of Cooling
- Law of cosines
- Can you help me po to solve this?
- Eliminate the Arbitrary Constants
Recent comments
- Yes.1 week 1 day ago
- Sir what if we want to find…1 week 1 day ago
- Hello po! Question lang po…3 weeks 5 days ago
- 400000=120[14π(D2−10000)]
(…1 month 4 weeks ago - Use integration by parts for…2 months 3 weeks ago
- need answer2 months 3 weeks ago
- Yes you are absolutely right…2 months 4 weeks ago
- I think what is ask is the…2 months 4 weeks ago
- $\cos \theta = \dfrac{2}{…3 months ago
- Why did you use (1/SQ root 5…3 months ago
The glass is falling at
The glass is falling at constant gravitational acceleration. From the formula s = vot + ½gt2; vo = 0 and g = 9.81 m/s2. Solving for t:
$t = \sqrt{\dfrac{2h}{g}}$
The sound is moving at constant velocity. From the formula s = vt, s = h and v = 340 m/s. Solving for t:
$t = \dfrac{h}{340}$
tglass + tsound = 3 seconds
$\sqrt{\dfrac{2h}{g}} + \dfrac{h}{340} = 3$
$h = 40.69 ~ \text{m}$
Thank you very much sir! This
Thank you very much sir! This will definitely help a lot in my review.