Problem A parabola has an equation of y^{2} = 8x. Find the equation of the diameter of the parabola, which bisect chords parallel to the line x – y = 4.

Answer Key

Solution

Slope of chords: $y' = m$

$y' = 1$

From the parabola: $y^2 = 8x$

$2y \, y' = 8$

$2y(1) = 8$

$y = 4$ ← Answer: [ C ]

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