A simply supported beam has a span of 12 m. The beam carries a total uniformly distributed load of 21.5 kN/m. 1. To prevent excessive deflection, a support is added at midspan. Calculate the resulting moment (kN·m) at the added support.
2. Calculate the resulting maximum positive moment (kN·m) when a support is added at midspan.
3. Calculate the reaction (kN) at the added support.
A uniformly distributed load of 300 lb/ft (including the weight of the beam) is simply supported on a 20-ft span. The cross section of the beam is described in Problem 1005. If n = 20, determine the maximum stresses produced in the wood and the steel.
A simply supported beam of length L carries a uniformly distributed load of 6000 N/m and has the cross section shown in Fig. P-585. Find L to cause a maximum flexural stress of 16 MPa. What maximum shearing stress is then developed?
A laminated beam is composed of five planks, each 6 in. by 2 in., glued together to form a section 6 in. wide by 10 in. high. The allowable shear stress in the glue is 90 psi, the allowable shear stress in the wood is 120 psi, and the allowable flexural stress in the wood is 1200 psi. Determine the maximum uniformly distributed load that can be carried by the beam on a 6-ft simple span.