Problem 02 | Elimination of Arbitrary Constants Problem 02 $y \sin x - xy^2 = c$ Solution 02 Click here to expand or collapse this section $y \sin x - xy^2 = c$ $(y \cos x~dx + \sin x~dy) - (2xy~dy + y^2~dx) = 0$ $y \cos x~dx + \sin x~dy - 2xy~dy - y^2~dx = 0$ $(y \cos x~dx - y^2~dx) + (\sin x~dy - 2xy~dy) = 0$ $y(\cos x - y)~dx + (\sin x - 2xy)~dy = 0$ answer Tags arbitrary constants first order differential equation Log in to post comments Book traversal links for Problem 02 | Elimination of Arbitrary Constants Problem 01 | Elimination of Arbitrary Constants Up Problem 03 | Elimination of Arbitrary Constants