The area of the diagonal section of a cube i equal to 36squareroot of 2. Determine the measures of the edge and the diagonal of the cube.
$A_{dotted} = 36\sqrt{2}$
$x(x \sqrt{2}) = 36\sqrt{2}$
$x^2 = 36$
$x = 6$
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$A_{dotted} = 36\sqrt{2}$
$x(x \sqrt{2}) = 36\sqrt{2}$
$x^2 = 36$
$x = 6$
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