Discussion on: Problem 346 | Equilibrium of Non-Concurrent Force System
Following is a discussion on the Reviewer item titled: Problem 346 | Equilibrium of Non-Concurrent Force System. Feel free to add your own comments!
Active forum topics
- Inverse Trigo
- General Solution of $y' = x \, \ln x$
- engineering economics: construct the cash flow diagram
- Eliminate the Arbitrary Constants
- Law of cosines
- Maxima and minima (trapezoidal gutter)
- Special products and factoring
- Integration of 4x^2/csc^3x√sinxcosx dx
- application of minima and maxima
- Sight Distance of Vertical Parabolic Curve
New forum topics
- Inverse Trigo
- General Solution of $y' = x \, \ln x$
- engineering economics: construct the cash flow diagram
- Integration of 4x^2/csc^3x√sinxcosx dx
- Maxima and minima (trapezoidal gutter)
- Special products and factoring
- Newton's Law of Cooling
- Law of cosines
- Can you help me po to solve this?
- Eliminate the Arbitrary Constants
Recent comments
- Yes.4 weeks ago
- Sir what if we want to find…4 weeks ago
- Hello po! Question lang po…1 month 2 weeks ago
- 400000=120[14π(D2−10000)]
(…2 months 2 weeks ago - Use integration by parts for…3 months 2 weeks ago
- need answer3 months 2 weeks ago
- Yes you are absolutely right…3 months 2 weeks ago
- I think what is ask is the…3 months 2 weeks ago
- $\cos \theta = \dfrac{2}{…3 months 3 weeks ago
- Why did you use (1/SQ root 5…3 months 3 weeks ago
Jhudiel
why do that 100lb is multiplied by 6?
Re: Jhudiel
In reply to Jhudiel by Jhudsss
to find the moment
Re: Jhudiel
In reply to Jhudiel by Jhudsss
sum of 3 distances: 2 + 2 + 2= 6