A student club on a college charges monthly membership dues of P10, less 5 centavos for each member over 60. How many members would give the club, the most revenue from the monthly dues?

Let R = monthly revenue x = number of student-member in excess of 60 x + 60 = total number of student-member

For number of members ≤ 60 monthly dues for each member = P10

For number of members > 60 monthly dues for each member = P(10 - 0.05x)

$R = 600 + 7x - 0.05x^2$

$\dfrac{dR}{dx} = 7 - 0.1x = 0$

$x = 70$

total number of members = 70 + 60 = 130 answer

thank you kaayu sir.

way sapayan

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Let

R = monthly revenue

x = number of student-member in excess of 60

x + 60 = total number of student-member

For number of members ≤ 60

monthly dues for each member = P10

For number of members > 60

monthly dues for each member = P(10 - 0.05x)

$R = 600 + 7x - 0.05x^2$

$\dfrac{dR}{dx} = 7 - 0.1x = 0$

$x = 70$

total number of members = 70 + 60 = 130

answerthank you kaayu sir.

way sapayan

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