How many permutations can be made out of the letters of the word ENGINEERING? Ans. 277, 200
$N = \dfrac{11!}{3! \times 3! \times 2! \times 2!}$
277200
More information about text formats
Follow @iMATHalino
MATHalino
$N = \dfrac{11!}{3! \times 3! \times 2! \times 2!}$
277200
Add new comment