Active forum topics
- Inverse Trigo
- General Solution of $y' = x \, \ln x$
- engineering economics: construct the cash flow diagram
- Eliminate the Arbitrary Constants
- Law of cosines
- Maxima and minima (trapezoidal gutter)
- Special products and factoring
- Integration of 4x^2/csc^3x√sinxcosx dx
- application of minima and maxima
- Sight Distance of Vertical Parabolic Curve
New forum topics
- Inverse Trigo
- General Solution of $y' = x \, \ln x$
- engineering economics: construct the cash flow diagram
- Integration of 4x^2/csc^3x√sinxcosx dx
- Maxima and minima (trapezoidal gutter)
- Special products and factoring
- Newton's Law of Cooling
- Law of cosines
- Can you help me po to solve this?
- Eliminate the Arbitrary Constants
Recent comments
- Yes.1 week 1 day ago
- Sir what if we want to find…1 week 1 day ago
- Hello po! Question lang po…3 weeks 5 days ago
- 400000=120[14π(D2−10000)]
(…2 months ago - Use integration by parts for…2 months 4 weeks ago
- need answer2 months 4 weeks ago
- Yes you are absolutely right…3 months ago
- I think what is ask is the…3 months ago
- $\cos \theta = \dfrac{2}{…3 months ago
- Why did you use (1/SQ root 5…3 months ago
Direction of Forces
The direction of force P as stated in the problem is up to the left but solved as up to the right. Suggested answer for the moment at point O is -6301.3 Nm.
Re: Direction of Forces
In reply to Direction of Forces by QIndustries13
Corrections are made to the problem... thanks.