The altitude of the storage bin shown in the sketch is 12ft and the bases are parallel rectangles having the dimensions indicated. Find the capacity.
$A_1 = 8 \times 7 = 56 ~ \text{ft}^2$
$A_2 = 14 \times 11 = 154 ~ \text{ft}^2$
$A_m = \dfrac{8 + 14}{2} \times \dfrac{7 + 11}{2} = 99 ~ \text{ft}^2$
$L = 12 ~ \text{ft}$
$V = \frac{1}{6}L(A_1 + 4A_m + A_2)$
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$A_1 = 8 \times 7 = 56 ~ \text{ft}^2$
$A_2 = 14 \times 11 = 154 ~ \text{ft}^2$
$A_m = \dfrac{8 + 14}{2} \times \dfrac{7 + 11}{2} = 99 ~ \text{ft}^2$
$L = 12 ~ \text{ft}$
$V = \frac{1}{6}L(A_1 + 4A_m + A_2)$
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