April 2020

Francis June E. Seraspe's picture

Minima maxima: a²y = x⁴

Submitted by Francis June E.... on April 8, 2020 - 2:34pm

How to solve a²y = x⁴

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Francis June E. Seraspe's picture

Minima Maxima: 9a³y=x(4a-x)³

Submitted by Francis June E.... on April 9, 2020 - 4:53pm

Patulong po ulit ako mam/sir
Yung process po sana ulit
9a²y=x(4a+x)³
Yung ans nya po is (a,3a) maximum
Thanks in advance mam/sir

Francis June E. Seraspe's picture

Minima Maxima: y=ax³+bx²+cx+d

Submitted by Francis June E.... on April 12, 2020 - 8:37pm

What is the condition that the cubic y=ax³+bx²+cx+d shall have two Extremes?

Answer nya po is b²-3ac>0
Salamat po.

Francis June E. Seraspe's picture

Minima maxima: Arbitrary constants for a cubic

Submitted by Francis June E.... on April 13, 2020 - 9:11am

Make the curve y=ax³+bx²+cx+d pass through the points (0,1)and (-3,7) and have a critical point at (-1,3)

Ans. y=-x³-4x²-5x+1
Thanks po

Francis June E. Seraspe's picture

Make the curve y=ax³+bx²+cx+d have a critical point at (0,-2) and also be a tangent to the line 3x+y+3=0 at (-1,0).

Submitted by Francis June E.... on April 13, 2020 - 8:01pm

Make the curve y=ax³+bx²+cx+d have a critical point at (0,-2) and also be a tangent to the line 3x+y+3=0 at (-1,0).
Ans nya po is y=x³+3x²-2. Salamat po

Francis June E. Seraspe's picture

Time rates: Question for Problem #12

Submitted by Francis June E.... on April 22, 2020 - 1:23pm

Paano po naging 64.03 mph ? Sa problem #12 po sa time rates. D ko pa po maintindihan sir