# Triaxial Deformation

## Solution to Problem 224 Triaxial Deformation

## Solution to Problem 223 Triaxial Deformation

**Problem 223**

## Shearing Deformation

**Shearing Deformation**

Shearing forces cause shearing deformation. An element subject to shear does not change in length but undergoes a change in shape.

The change in angle at the corner of an original rectangular element is called the shear strain and is expressed as

$\gamma = \dfrac{\delta_s}{L}$

The ratio of the shear stress τ and the shear strain γ is called the *modulus of elasticity in shear* or modulus of rigidity and is denoted as G, in MPa.

$G = \dfrac{\tau}{\gamma}$

The relationship between the shearing deformation and the applied shearing force is

$\delta_s = \dfrac{VL}{A_s G} = \dfrac{\tau L}{G}$

where V is the shearing force acting over an area A_{s}.

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