Solve for x if log_x 8 = 3/4.

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Solution by Change Base Rule of Logarithm
$\log_x 8 = 3/4$

$\dfrac{\log 8}{\log x} = \dfrac{3}{4}$

$\log x = \frac{4}{3} \log 8$

$x = 16$
 

Solution by Logarithmic to Exponential Form
$\log_x 8 = 3/4$

$x^{3/4} = 8$

$x = 8^{4/3}$

$x = 16$