Solve for the determinants: $\begin{vmatrix}1 & 2 & 3 \\ 2 & -1 & 4 \\-1 & -1 & -5\end{vmatrix}$ Solve for the determinant of $\begin{vmatrix} 1 & 2 & 3 \\ 2 & -1 & 4 \\ -1 & -1 & -5 \end{vmatrix}$ A. 10 C. 14 B. 12 D. 16 Solution Click here to… Jhun Vert Fri, 06/07/2024 - 18:23 Solution Click here to expand or collapse this section $D = \begin{vmatrix} 1 & 2 & 3 \\ 2 & -1 & 4 \\ -1 & -1 & -5 \end{vmatrix}$ $D = \left| \begin{matrix} 1 & 2 & 3 \\ 2 & -1 & 4 \\ -1 & -1 & -5 \\ \end{matrix} \left| \, \begin{matrix} 1 & 2 \\ 2 & -1 \\ -1 & -1 \\ \end{matrix} \right. \right|$ $D = \text{Sum of product of downward diagonals} - \text{Sum of product of upward diagonals}$ $D = \left[ 1(-1)(-5) + 2(4)(-1) + 3(2)(-1) \right] - \left[ -1(-1)(3) + (-1)(4)(1) + (-5)(2)(2) \right]$ $D = (5 - 8 - 6) - (3 - 4 -20)$ $D = -9 - (-21)$ $D = -9 + 21$ $D = 12$ Recommended Solution Use the matrix function of your calculator Log in or register to post comments Log in or register to post comments
Solution Click here to… Jhun Vert Fri, 06/07/2024 - 18:23 Solution Click here to expand or collapse this section $D = \begin{vmatrix} 1 & 2 & 3 \\ 2 & -1 & 4 \\ -1 & -1 & -5 \end{vmatrix}$ $D = \left| \begin{matrix} 1 & 2 & 3 \\ 2 & -1 & 4 \\ -1 & -1 & -5 \\ \end{matrix} \left| \, \begin{matrix} 1 & 2 \\ 2 & -1 \\ -1 & -1 \\ \end{matrix} \right. \right|$ $D = \text{Sum of product of downward diagonals} - \text{Sum of product of upward diagonals}$ $D = \left[ 1(-1)(-5) + 2(4)(-1) + 3(2)(-1) \right] - \left[ -1(-1)(3) + (-1)(4)(1) + (-5)(2)(2) \right]$ $D = (5 - 8 - 6) - (3 - 4 -20)$ $D = -9 - (-21)$ $D = -9 + 21$ $D = 12$ Recommended Solution Use the matrix function of your calculator Log in or register to post comments
Solution Click here to…