Please help. I need it asap.
Solve the linear differential equation:
(D5–12D4+52D3–112D2+192D–256)y = 0
When I factored it out. I got (D-4)^3 (D^2 +4)
With D-4..
My equation will be Y= (C1 + C2x + C3x^2)e^4x
But how about my D^2 + 4?
How can I add that in my equation?
D^2 +4 will actually be $C_4 \cos 2x + C_5 \sin 2x$
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