another problem :(
a car if nass 1600kg coast down a 10 percent grade from A to B, a distance of 30m and then coast along a level road until it stops at C. assume the road resistance to remain constant of 200N for the entire distance A to C, if the initial velocity of the car at A is 25kph, compute:
a.) its velocity at B
b.) the distance s it coast from B to C.
Re: another problem :(
Motion from A to B
[12(1600)(253.6)2+1600(9.81)(30√101)]−200(30)=EB
EB=79,434.56 N⋅m
12(1600)(vB3.6)2=79,434.56
vB=35.87 kph
Motion from B to C
79,434.56−200sBC=0
sBC=397.17 m