General Solution of $y' = x \, \ln x$
Determine the general solution of the differential equation given by:
y'=xlnx
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need answer
need answer
Use integration by parts for…
Use integration by parts for $\displaystyle y = \int x \, \ln x ~ dx$. The answer is $y = \frac{1}{2}x^2 \ln x - \frac{1}{4}x^2 + C$.