Two Gamblers Play Until One is Bankrupt: Chance That the Better Player Wins Date of Exam November 2016 Subject Mathematics, Surveying and Transportation Engineering Problem Player M has Php1, and Player N has Php2. Each play gives one the players Php1 from the other. Player M is enough better than player N that he wins 2/3 of the plays. They play until one is bankrupt. What is the chance that Player M wins? A. 3/4 C. 4/7 B. 5/7 D. 2/3 Answer Key Click here to show or hide the answer key [ C ] Solution Click here to expand or collapse this section W = win L = lose Player M wins: P=WW+WLWW+WLWLWW+WLWLWLWW+… P=W2+(WL)W2+(WL)2W2+(WL)3W2+… P=(23)2+(23⋅13)(23)2+(23⋅13)2(23)2+(23⋅13)3(23)2+… Sum of Infinite Geometric Progression P=a11−r=(23)21−(23⋅13) P=4/7 ← Answer: [ C ] Category Statistics and Probability Probability Gambler's Ruin Log in or register to post comments