Equivalent Cartesian Equation of Parametric Equations Date of Exam May 2016 Subject Mathematics, Surveying and Transportation Engineering Problem Find the Cartesian equation of the curve represented by $x = 4t + 3$ and $y = 16t^2 - 9$, -∞ < t < +∞. A. $y = x^2 + 6x$ C. $y = x^2 + 4x$ B. $y = x^2 - 6x$ D. $y = x^2 - 4x$ Answer Key Click here to show or hide the answer key [ B ] Solution Click here to expand or collapse this section $x = 4t + 3$ $t = \dfrac{x - 3}{4}$ $y = 16t^2 - 9$ $y = 16\left( \dfrac{x - 3}{4} \right)^2 - 9$ $y = x^2 - 6x$ ← answer Category Analytic Geometry Parametric Equations Cartesian Equation Log in or register to post comments
