Equivalent Cartesian Equation of Parametric Equations Reconstructed problem similar to CE board exam dated May 2016 Subject Mathematics, Surveying and Transportation Engineering Problem Find the Cartesian equation of the curve represented by $x = 4t + 3$ and $y = 16t^2 - 9$, -∞ < t < +∞. A. $y = x^2 + 6x$ C. $y = x^2 + 4x$ B. $y = x^2 - 6x$ D. $y = x^2 - 4x$ Answer Key Click here to show or hide the answer key [ B ] Solution Click here to expand or collapse this section $x = 4t + 3$ $t = \dfrac{x - 3}{4}$ $y = 16t^2 - 9$ $y = 16\left( \dfrac{x - 3}{4} \right)^2 - 9$ $y = x^2 - 6x$ ← answer Category Analytic Geometry Parametric Equations Cartesian Equation Log in or register to post comments
