If x varies directly as y and inversely as z and x = 14 when y = 7, and z = 2. Find x when y = 16 and z = 4.
If x varies directly as y and inversely as z and x = 14 when y = 7, and z = 2. Find x when y = 16 and z = 4.
If x varies directly as y and inversely as z and x = 14 when y = 7, and z = 2. Find x when y = 16 and z = 4.
If z varies directly as x and inversely as the square of y, and z = 1/3, x = 4, and y = 6, find z when x = 12 and y = 4.
The altitude of the storage bin shown in the sketch is 12ft and the bases are parallel rectangles having the dimensions indicated. Find the capacity.
All logged in users can include math equations in their posts and it is easy to do. Inline equations can be written between dollar signs and centered equations are between double dollar signs.
Example:
If you write $x = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}$
will result to $x = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}$. This an example of inline equation. If you wish to center your equation, you can write $$x = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}$$
and it will result to this $$x = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}$$ which is a centered equation.
Problem
The median of a right triangle drawn to the hypotenuse is 3 cm long and makes an angle of 60° with it. Find the area of the triangle.
A. 7.97 cm2 | C. 8.79 cm2 |
B. 8.97 cm2 | D. 7.79 cm2 |
Problem
By the conditions of a will, the sum of P2.5M is left to a girl to be held in a trust fund by her guardian until it amounts to P4.5M. When will the girl receive the money if the fund is invested at 8% compounded quarterly?
A. 7 years | C. 7.42 years |
B. 6.8 years | D. 7.25 years |
Problem
For triangle BOA, B is on the y-axis, O is the origin, and A is on the x-axis. Point C(5, 2) is on the line AB. Find the length of AB if the area of the triangle is 36 unit2.
A. 24.31 units | C. 13.42 units |
B. 18.30 units | D. 10.80 units |
Hello, can anyone solve this equation?
I can't figure it out,
$(1-xy)^{-2} dx + \left[ y^2 + x^2 (1-xy)^{-2} \right] dy = 0$
Thanks.
Can anyone solve this D. E.?
y' = x^3 - 2xy, where y(1)=1
and
y' = 2(2x-y) that passes through (0,1)