September 2016

( 2x³ - y⁴) dx + xy³ dy= 0

2xy y' = y^2 - 2 x^2

(y^4 - 2xy) dx + 3 x^2 dy= 0

y' = y - x y^3 e^ -2 x

Please help. I need it asap.

Solve the linear differential equation:
(D5–12D4+52D3–112D2+192D–256)y = 0

When I factored it out. I got (D-4)^3 (D^2 +4)

With D-4..

My equation will be Y= (C1 + C2x + C3x^2)e^4x

But how about my D^2 + 4?

How can I add that in my equation?

A distance of 1000 ft is to be taped with an error of not more than +- .10 ft Determine how accurately each 100 ft length must be measured to ensure the error will not exceed the permissible limit.