## Solution to Problem 577 | Horizontal Shearing Stress

**Problem 577**

A plywood beam is built up of 1/4-in. strips separated by blocks as shown in Fig. P-577. What shearing force V will cause a maximum shearing stress of 200 psi?

**Problem 577**

A plywood beam is built up of 1/4-in. strips separated by blocks as shown in Fig. P-577. What shearing force V will cause a maximum shearing stress of 200 psi?

**Problem 576**

Rework Prob. 575 assuming that the web is 200 mm instead of 160 mm.

**Problem 575**

Determine the maximum and minimum shearing stress in the web of the wide flange section in Fig. P-575 if V = 100 kN. Also, compute the percentage of vertical shear carried only by the web of the beam.

**Problem 574**

In the beam section shown in Fig. P-574, prove that the maximum horizontal shearing stress occurs at layers h/8 above or below the NA.

**Problem 572**

The T section shown in Fig. P-572 is the cross-section of a beam formed by joining two rectangular pieces of wood together. The beam is subjected to a maximum shearing force of 60 kN. Show that the NA is 34 mm from the top and the I_{NA} = 10.57 × 10^{6} mm^{4}. Using these values, determine the shearing stress (a) at the neutral axis and (b) at the junction between the two pieces of wood.

**Problem 571**

For a beam with the same cross section as that in Prob. 570, plot the shearing stress distribution across the section at a section where the shearing force is V = 1800 lb.

**Problem 570**

A uniformly distributed load of 200 lb/ft is carried on a simply supported beam span. If the cross-section is as shown in Fig. P-570, determine the maximum length of the beam if the shearing stress is limited to 80 psi. Assume the load acts over the entire length of the beam.

**Problem 569**

Show that the maximum shearing stress in a beam having a thin-walled tubular section of net area A is τ = 2V / A.

**Problem 568**

Show that the shearing stress developed at the neutral axis of a beam with circular cross section is τ = (4/3)(V / π r^{2}). Assume that the shearing stress is uniformly distributed across the neutral axis.