04 - Age-related Problem in Algebra Jhun Vert Fri, 04/17/2020 - 06:33 pm

Problem
Albert is as old as Bryan will be when Albert is twice as old as Bryan was when Albert's age was half the sum of their present ages. Bryan is as old as Albert was when Bryan was half the age he will be ten years from now. How old are Albert and Bryan?
 

albert-and-bryan.jpg

 

03 - Age-related Problem in Algebra Jhun Vert Fri, 04/17/2020 - 06:31 pm

Problem
Mary is 24 years old. Mary is twice as old as Anna was when Mary was as old as Anna is now. How old is Anna now?
 

mary-and_anna.jpg

 

02 - Age-related Problem in Algebra Jhun Vert Fri, 04/17/2020 - 06:30 pm

Problem
The sum of the parents' ages is twice the sum of their children’s ages. Five years ago, the sum of the parents' ages was four times the sum of their children’s ages. In fifteen years, the sum of the parents' ages will be equal to the sum of their children’s ages. How many children were in the family?
 

01 - Age-related Problem in Algebra Jhun Vert Fri, 04/17/2020 - 06:28 pm

Problem
Alfred is four times as old as his nephew Franco. 5 years ago, the sum of their ages is equal to the present age of Alfred. How old is each?
 

Age-related Problems Jhun Vert Fri, 04/17/2020 - 05:06 pm

If x = present age of a person
x – 3 = age of the person 3 years ago
x + 5 = age of the person 5 years from now or 5 years hence
 

Note:
The difference of the ages of two persons is constant at any time.
 

09 - Number of CEs, EEs, and MEs and their Average Ages Jhun Vert Fri, 04/17/2020 - 04:57 pm

Problem
In an organization there are CE’s, EE’s and ME’s. The sum of their ages is 2160; the average age is 36; the average age of CE’s and EE’s is 39; the average age of EE’s and ME’s is 32 and 8/11; the average age of the CE’s and ME’s is 36 and 2/3. If each CE had been 1 year older, each EE 6 years and each ME 7 years older, their average age would have been greater by 5 years. Find the number of CE, EE, and ME in the group and their average ages.