Active forum topics
- Ceva’s Theorem Is More Than a Formula for Concurrency
- The Chain Rule Explained: Don't Just Memorize, Visualize It
- The Intuition Behind Integration by Parts (Proof & Example)
- Statics
- Calculus
- Hydraulics: Rotating Vessel
- Inverse Trigo
- Application of Differential Equation: Newton's Law of Cooling
- Problems in progression
- General Solution of $y' = x \, \ln x$
New forum topics
- Ceva’s Theorem Is More Than a Formula for Concurrency
- The Chain Rule Explained: Don't Just Memorize, Visualize It
- The Intuition Behind Integration by Parts (Proof & Example)
- Statics
- Calculus
- Hydraulics: Rotating Vessel
- Inverse Trigo
- Problems in progression
- General Solution of $y' = x \, \ln x$
- engineering economics: construct the cash flow diagram
Recent comments
- Wow! :>2 weeks ago
- In general, the centroid of …2 weeks 3 days ago
- isn't the centroid of the…2 weeks 3 days ago
- I get it now, for long I was…1 month ago
- Why is BD Tension?
is it not…1 month ago - Bakit po nagmultiply ng 3/4…2 months 3 weeks ago
- Determine the least depth…1 year ago
- Solve mo ang h manually…2 months 3 weeks ago
- Paano kinuha yung height na…1 year 1 month ago
- It's the unit conversion…1 year 1 month ago


Re: Water supply
Velocity
$v = 2 ~ \dfrac{\text{m}}{\text{s}} \times \dfrac{3600 ~ \text{s}}{1 ~ \text{hr}} = 7200 ~ \text{m/hr}$
Discharge, Q = Velocity, v × Area, A or
$Q = vA$
$12 = 7200 \times \pi r^2$
$r = 0.023 ~ \text{ m} = 2.3 ~ \text{ cm}$