From the following figure, which of the following is equal to $\tan (\theta/2)$?

From the following figure, which of the following is equal to $\tan (\theta/2)$?

basic_016-half-angle-formulas-derivation.gif

 

A. $\tan (\theta/2) = \begin{cases} \dfrac{\sin \theta}{1 - \cos \theta} \\ \, \\ \dfrac{1 - \cos \theta}{\sin \theta} \end{cases}$ C. $\tan (\theta/2) = \begin{cases} \dfrac{\sin \theta}{1 + \cos \theta} \\ \, \\ \dfrac{1 + \cos \theta}{\sin \theta} \end{cases}$
B. $\tan (\theta/2) = \begin{cases} \dfrac{\sin \theta}{1 - \cos \theta} \\ \, \\ \dfrac{1 + \cos \theta}{\sin \theta} \end{cases}$ D. $\tan (\theta/2) = \begin{cases} \dfrac{\sin \theta}{1 + \cos \theta} \\ \, \\ \dfrac{1 - \cos \theta}{\sin \theta} \end{cases}$

Jhun Vert Sat, 06/15/2024 - 16:12

Solution