The graph of y = ax^2 + c has its vertex at (0, 4) and passes through the point (3, -5)
The graph of y = ax2 + c has its vertex at (0, 4) and passes through the point (3, -5). Find the value of a.
| A. -1 | C. 1 |
| B. -2 | D. 2 |
May 2017
Solve for the determinants: $\begin{vmatrix}1 & 2 & 3 \\ 2 & -1 & 4 \\-1 & -1 & -5\end{vmatrix}$
Solve for the determinant of $\begin{vmatrix}
1 & 2 & 3 \\
2 & -1 & 4 \\
-1 & -1 & -5
\end{vmatrix}$
| A. 10 | C. 14 |
| B. 12 | D. 16 |
Solve for $x$ if $\begin{vmatrix}x & 2 \\ 5 & 3\end{vmatrix} = 8$
Solve for x if $\begin{vmatrix}
x & 2 \\
5 & 3
\end{vmatrix} = 8$
| A. 4 | C. 6 |
| B. 5 | D. 7 |
Evaluate $\begin{vmatrix}8 & -20 \\ 4 & 10\end{vmatrix}$.
Evaluate $\begin{vmatrix}
8 & -20 \\ 4 & 10
\end{vmatrix}$.
| A. 120 | C. 160 |
| B. 140 | D. 180 |
A student in a chemistry laboratory wants to form a 32 milliliter mixture of two solutions to contain 30% acid.
A student in a chemistry laboratory wants to form a 32 milliliter mixture from two solutions to contain 30% acid. Solution A contains 42% acid and solution B contains 18% acid. How many milliliters of each solution must be used?
| A. A = 16, B = 16 | C. A = 10, B = 22 |
| B. A = 14, B = 18 | D. A = 15, B = 17 |
A line with equation ax + by = 3 passes through (6, 3) and (-1, -1). Find a and b without finding the slope.
A line with equation $ax + by = 3$ passes through (6, 3) and (-1, -1). Find a and b without finding the slope.
| A. a = 4, b = -7 | C. a = 2, b = -4 |
| B. a = 3, b = 6 | D. a = 4, b = 4 |
Find the equation of a line having a slope of 2 and y-intercept of 3.
Find the equation of a line having a slope of 2 and y-intercept of 3.
| A. $x - 2y + 4 = 0$ | C. $2x - 3y + 4 = 0$ |
| B. $2x - y + 3 = 0$ | D. $x + 2y - 8 = 0$ |
Find the equation of a line with slope 2/3 passing through point (0, -5).
Find the equation of a line with slope 2/3 passing through point (0, -5).
| A. $3x - 2y + 10 = 0$ | C. $2x - 3y - 15 = 0$ |
| B. $x - 2y - 12 = 0$ | D. $2x + 3y + 12 = 0$ |
Find the slope of the line determined by the points (-3, 4) and (1, -6).
Find the slope of the line determined by the points (-3, 4) and (1, -6).
| A. -2/5 | C. -3/4 |
| B. -5/2 | D. -4/3 |
Simplify $2\sqrt{8x^3} + 3x\sqrt{32x} - x\sqrt{18x}$
Simplify $2\sqrt{8x^3} + 3x\sqrt{32x} - x\sqrt{18x}$
| A. $10x\sqrt{3x}$ | C. $12x\sqrt{3x^3}$ |
| B. $9x\sqrt{5x}$ | D. $13x\sqrt{2x}$ |