The graph of y = ax^2 + c has its vertex at (0, 4) and passes through the point (3, -5)
The graph of y = ax2 + c has its vertex at (0, 4) and passes through the point (3, -5). Find the value of a.
| A. -1 | C. 1 |
| B. -2 | D. 2 |
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MATHalinoEngineering Math ReviewThe graph of y = ax2 + c has its vertex at (0, 4) and passes through the point (3, -5). Find the value of a.
| A. -1 | C. 1 |
| B. -2 | D. 2 |
Solution Click here to…