The graph of y = ax^2 + c has its vertex at (0, 4) and passes through the point (3, -5) The graph of y = ax2 + c has its vertex at (0, 4) and passes through the point (3, -5). Find the value of a. A. -1 C. 1 B. -2 D. 2 Log in or register to post comments Solution Click here to… Jhun Vert Fri, 06/07/2024 - 18:25 Solution Click here to expand or collapse this section $y = ax^2 + c$ At (0, 4) $4 = a(0^2) + c$ $c = 4$ At (3, -5) $-5 = a(3^2) + 4$ $a = -1$ Log in or register to post comments
Solution Click here to… Jhun Vert Fri, 06/07/2024 - 18:25 Solution Click here to expand or collapse this section $y = ax^2 + c$ At (0, 4) $4 = a(0^2) + c$ $c = 4$ At (3, -5) $-5 = a(3^2) + 4$ $a = -1$ Log in or register to post comments
Solution Click here to…